Question

Помогите решить номер 4

Answer 1

$left { {{3^{2x-6}<frac{1}{27}} atop {log_3(1-x)^2 leq 2}} right. ; left { {{3^{2x-6}<3^{-3}} atop {(1-x)^2 leq 3^2}} right. ; left { {{2x-6<-3} atop {(1-x-3)(1-x+3) leq 0}} right. \\ left { {{x<frac{3}{2}} atop {(-2-x)(4-x) leq 0}} right. ; left { {{x<1,5} atop {(x+2)(x-4) leq 0}} right. ; left { {{x<1,5} atop {-2 leq x leq 4}} right. ; to \\xin [-2;; 1,5)$ 

Целые решения: х=-2,-1,0,1.