Question

6а^2+3ab^2-4ab-2b^3, при а= -1 1/8

b= -1 1/2

Answer 1

6a^2+3ab^-4ab-2b^2 = 2a(3a-2b)+b^2(3a-2b) = (3a-2b)(2a+b^2)

Если a=(-1 1/8), b=(-1 1/2), то (3*(-1 1/8) - 2*(-1 1/2))(2*(-1 1/8) + (-1 1/2)^2) = (3.375 - 3)(-2.25+2.25) = 0