Question

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Answer 1

$dfrac{sin 2 alpha }{1+cos 2 alpha } = dfrac{2sin alphacdotcos alpha }{1+2cos^2 alpha-1 } = dfrac{sin alpha }{cos alpha } =tan alpha$

Answer 2

$frac{sin2 alpha }{1+cos2 alpha } = frac{2sin alpha cos alpha }{sin^{2} alpha +cos^{2} alpha +cos^{2} alpha -sin^{2} alpha } = frac{2sin alpha cos alpha }{2cos^{2} alpha } = frac{sin alpha }{cos alpha } =tg alpha$