Question

(3cos(-2п - B) +3sin(-п/2 + B))/2cos ( B+3п)

Answer 1

$(3cos(-2 pi - beta )+frac{3sin(- frac{ pi }{2} + beta ) }{ 2 cos(beta +3 pi )} = \ 3cos beta + frac{ 3cos beta }{2cos beta } =3cos beta +1.5$