Question

$4 ^{3/2} + 8 ^{2/3} + sqrt{49} = ?$

Answer 1

$4^{frac{3}{2}}+8^{frac{2}{3}}+sqrt{49}=\\(2^2)^{frac{3}{2}}+(2^3)^{frac{2}{3}}+sqrt{7^2}=\\2^{(2*frac{3}{2})}+2^{(3*frac{2}{3})}+7=2^3+2^2+7=8+4+7=19$

Answer 2

$4^{3/2}+8^{2/3}+ sqrt{49}=2^{ frac{2*3}{2}}+2^{ frac{3*2}{3}}+7=2^3+2^2+7=8+4+7=19$