Question

Решите систему уравнений:

$left { {{2x+y^{2} =6} atop {x+y=3}} right.$

Answer 1

$left { {{2x+y^{2} =6} atop {x+y=3}} right. \\ left { {{2x+y^{2} =6} atop {x=3-y}} right. \\2(3-y)+y^2=6\\y^2-2y=0\\y(y-2)=0\\y_1=0;quad y_2=2\\\x_1=3-y_1=3-0=3\\x_2=3-y_2=3-2=1\\Otvet: (3,0);(1,2)$