Question

$15 x^{2} < frac{1}{225}$  
 $0.5 ^{8-x} =1$
$left { {{5x+2y=100} atop {lgx-lgy=lg16-1}} right.$
$sqrt{1-x}.sqrt{x} =x$
$( sqrt{1,2} ) ^{4,2} ; ( sqrt{1,2} ) ^{0,2}$

Answer 1

$15x^2< frac{1}{225}$

$x^2< frac{1}{255}:15$

$x^2< frac{1}{255}* frac{1}{15}$

$x^2< frac{1}{3375}$

$x_1< -frac{1}{15 sqrt{15} } ; x_2= frac{1}{15 sqrt{15} }$

Ответ: $(- frac{1}{15 sqrt{15} }; frac{1}{15 sqrt{15} })$


$0,5^{8-x}=1$
$0,5^8*0,5^{-x}=0,5^0$
$8-x=0$
$-x=-8$
$x=8$


$sqrt{1-x}* sqrt{x} =x$
$x(1-x)=x^2$
$x-x^2-x^2=0$
$x-2x^2=0$
$x(1-2x)=0$
$x_1=0$
$1-2x=0$
$2x=1$
$x_2= frac{1}{2}$