Question

Расчитать ph 0,1 M раствора CH3COOH
k CH3COOH=1,74×10 в минус пятой степени

Answer 1

CH3COOH---->$CH3COO^{-} + H^{+}$
k=$frac{[CH3COO^{-}][ H^{+} ]}{0,1 }$
1,74*10⁻⁵ = [H⁺]²/0,1
[H⁺]²=1,74*10⁻⁶
[H⁺]=1,32*10⁻³
pH=2,88