Question

Решить уравнение: y=x^2+4x-3, f(x)=(x+1)*(2x-3), y=f(x)

Answer 1

y = x^2+4x-3
 f(x) = (x+1)*(2x-3)
 y = f(x)

x^2 + 4x - 3 = (x+1)*(2x-3)
x^2 + 4x - 3 = 2x^2 - x - 3 
x^2 - 5x = 0 
x( x - 5) = 0
x = 0 
x = 5 

Answer 2

x^2+4x-3=(x+1)*(2x-3)
x^2+4x-3= 2x^2-3x+2x-3
x^2+4x-3-2x^2+x+3=0
-x^2+5x=0
x^2-5x=0
x(x-5)=0
x=0 и x = 5