Question

Найдите корень уравнения

Answer 1

$sqrt{ frac{17+x}{-x} } =3 \ frac{17+x}{-x} geq 0 \ x neq 0 14+x=0 \ x geq -17 \ (sqrt{ frac{17+x}{-x} } )^{2} =3^{2} \ frac{17+x}{-x} =9 /*(-x)\ 17+x=-9x \ x+9x=-17 \ 10x=-17 \ x=-1.7$