Question

Помогите решить cos12x-sin4x=0

Answer 1

sin(π/2-12x) -sin4x=0
2sin(π/4-8x)cos(π/4-4x)=0
sin(π/4-8x)=0
π/4-8x=πn
-8x=-π/4+πn
x=π/32+πn/8
cos(π/4-4x)=0
π/4-4x=π/2+πn
-4x=-π/4+π/2+πn
-4x=π/4+πn
x=-π/16+πn/4