Question

найти интеграл (3х-1)^2 dx

Answer 1

S(3x-1)²dx=S(9x²-6x+1)dx=3x³-3x²+x+c

Answer 2

$y=(3x-1)^2=(3x)^2-2cdot3xcdot1+1^2=9x^2-6x+1\\intleft(9x^2-6x+1right)dx=frac{1}{3}cdot9x^3-frac{1}{2}cdot6x^2+x+C=3x^3-3x^2+x+C$