Question

Помогите найти производную функции

Answer 1

( 8xtg3x-(4x²-2)*3cos²3x ) tg²3x =  

( 8xsin3xcos3x - (12x²-6)cox²3x) tg²3x =

(4xsin6x-12x²+6)    sin²3x

Answer 2

$frac{4x^2-2}{tg3x} = frac{8xtg3x-frac{12x^2-6 }{cos^23x} }{tg^23x} \ \ (tg3x)'=3(frac{sin3x}{cos3x})'=3* frac{cos^23x+sin^23x}{cos^23x} = frac{3}{cos^23x}$