Question

(2х+7)(3х-1)-(5х-1)(х+3)=(х+1)^2

Answer 1

$\(2x+7)(3x-1)-(5x-1)(x+3)=(x+1)^2 \ \6x^2-2x+21x-7-5x^2-15x+x+3=x^2+2x+1 \ \5x-2x=1+4 \ \3x=5 \ \x=frac53=1frac23$

Answer 2

6x^2 + 21x - 2x - 7 - 5x^2 + x - 15x + 3 = x^2 + 2x +1
x^2 + 5x - 4 -x^2 - 2x -1 = 0
3x = 5
x = 1 2/3