Question

РЕШИТЕ ПРАВИЛЬНО ПОЛУЧИТЕ 102 ПНК 

Answer 1

решил, правильно или нет решать вам

Answer 2

3) 4x-13<7x-1                       5x+16>9x+4

4x-7x<-1+13                          5x-9x>4-16

-3x<12                                   -4x>-12

x>-12/3                                   x<12/4

x>-4                                        x<3

    

-4<x<3      (-4;3)

 

№) x^2-8x+16=0

x1+x2=8

x1*x2=16

x1=x2=4

 

 

$(frac{x-3}{(x-4)(x-4)}-frac{x+5}{(x-4)(x+4)})^{-1}frac{8(x+2)}{(x-4)(x+4)}+11=\\= (frac{(x-3)(x+4)-(x+5)(x-4)}{(x-4)(x-4)(x+4)})^{-1}frac{8(x+2)}{(x-4)(x+4)}+11=\\= frac{(x-4)(x-4)(x+4)}{x^{2}-3x+4x-12-x^{2}+4x-5x+20}cdotfrac{8(x+2)}{(x-4)(x+4)}+11=\\= frac{(x-4)(x-4)(x+4)8(x+2)}{8(x-4)(x+4)}+11=(x-4)(x+2)+11<var>=\\=</var>x^{2}-4x+2x-8+11=x^{2}-2x+3$

 

 

1) $(frac{a+2}{a-2}- frac{a-2}{a+2}) (frac{-(a^2-4)}{a^{2}+4})= (frac{(a+2)(a+2)-(a-2)(a-2)}{(a-2)(a+2)})(frac{-(a^2-4)}{a^{2}+4})=\\= (frac{a^{2}+4a+4-a^{2}+4a-4}{(a-2)(a+2)})(frac{-(a^2-4)}{a^{2}+4})=frac{-8a(a^2-4)}{(a^{2}-4)(a^{2}+4)}=-frac{8a}{a^{2}+4}$

 

2)$5sqrt{12}+frac{1}{4}sqrt{48}-6sqrt{75}=5sqrt{4}sqrt{3}+frac{1}{4}sqrt{16}sqrt{3}-6sqrt{25}sqrt{3}=\=10sqrt{3}+sqrt{3}-30sqrt{30}=-19sqrt{3}$