Question

Решите номер 21.Есть вложение.

Answer 1

$(frac{2}{a-2}-frac{3a+6}{(a-2)(a+3)}+ frac{2a}{a+3})*frac{a}{2a-5}=frac{2a+6-3a-6+2a^{2}-4a}{(a-2)(a+3)}*frac{a}{2a-5}= \ =frac{2a^{2}-5a}{(a-2)(a+3)}*frac{a}{2a-5}=frac{a(2a-5)*a}{(a-2)(a+3)(2a-5)}= frac{a^{2}}{(a-2)(a+3)}$