Question

Найдите корень уравнения:

8y-3(2y-3)=7y-2(5y+8)

Answer 1

8y-3(2y-3)=7y-2(5y+8)
8у-6у+9=7у-10у-16
8у-6у-7у+10у=-9-16
5у=-25
у=-5

Answer 2

$8y-3(2y-3)=7y-2(5y+8) \ 8y-6y+9=7y-10y-16 \ 8y-6y-7y+10y=-16-9 \ 5y=-25 \ y=-5$