Question

решите систему уравнений {X+Y=-2; X"2+Y"2=100

Answer 1

x + y = - 2
x^2 + y^2 = 100

x = - 2 - y 
( - 2 - y)^2 + y^2 - 100 = 0 **

**
y^2 + 4y + 4 + y^2 - 100 = 0 
2y^2 + 4y - 96 = 0  //:2
y^2 + 2y - 48 = 0 
y = - 8
y = 6 

y = 6 
x = - 2 - 6 = - 8

y = - 8
x = - 2 + 8 = 6

ОТВЕТ:
( - 8; 6) ; ( 6 ; - 8)