Question

(X-2)×(X-3)²×(X-4)=20

Answer 1

$(x-2)(x-4)cdot(x-3)^2=20\ (x^2-6x+8)(x^2-6x+9)=20\ t=x^2-6x+9:\ (t-1)t=20\ t^2-t-20=0\ t_1=5;quad t_2=-4\ left[begin{array}{l} (x-3)^2=5\ (x-3)^2=-4<0 end{array}right.\ (x-3)^2=5\ boxed{x=3pmsqrt5}$