Question

Сократите дробь:
а)48p^3q^4/36p^2q^3;
б)x^2+6x+9/x^2-9

Answer 1

а)48p^3q^4/36p^2q^3=8p*q6=4p*q3
б)x^2+6x+9/x^2-9=x+3(x-3)*(x+3)=1x-3
x^2+6x+9=0
D=36-4*9=0
x=-62=-3