Question

3tg п/4 - sin^2 п/3 + cos^2 п/6

Answer 1

$3tgfrac{pi}{4} -sin^2frac{pi}{3} +cos^2frac{pi}{6} =3cdot 1-(frac{sqrt{3}}{2} )^2+(frac{sqrt{3}}{2} )^2=3$