Question

-2x^2-2x+5=x^2-x-(1+x^2)
заранее спасибо :)

Answer 1

-2x^2-2x+5=x^2-x-1-x^2
-2x^2-2x+5=-x-1
-2x^2-x+6=0
2x^2+x-6=0
D=1+4*2*6=49
x= (-1 +- 7)/4
x1= 1,5
x2= -2

Answer 2

$-2 x^{2} -2x+5= x^{2} -x-(1+ x^{2} ) \ -2 x^{2} -2x+5= x^{2} -x-1- x^{2} \ -2 x^{2} -2x+5=-x-1 \ -2 x^{2} -2x+5+x+1=0 \ -2 x^{2} -x+6=0/*(-1) \ 2 x^{2} +x-6=0 \ D=1+48=49 \ sqrt{D} =7\ x_{1} = frac{-1-7}{4} = frac{-8}{4} =-2 \ x_{2} = frac{-1+7}{4} = frac{6}{4} = frac{3}{2} =1 frac{1}{2} =1 frac{5}{10} =1.5$