Question

Помогите ,пожалуйста;)
(12х-1)(6х-1)(4х-1)(3х-1)=5

Answer 1

(12x-1)(3x-1) * (6x-1)(4x-1) = 5
(36x^2-6x+1)* (24x^2-2x+1) - 5 = 0
36x^2-15x+4=0
D = b^2-4ac = (-15)^2 -4*36*4 = -351
D<0
x1=-1/12;
x2=1/2