Question

2х^2-3/х-2 - 4х-3/х-2 = 0

Answer 1

$frac{2x^2-3}{x-2}-frac{4x-3}{x-2}=0 \ \ ODZ: \ x-2 neq 0 \ x neq 2 \ \ frac{(2x^2-3)-(4x-3)}{x-2}=0 \ \ frac{2x^2-4x}{x-2}=0 \ \ frac{2x(x-2)}{x-2}=0 \ \ 2x=0 \ x=0$