Question

решите уравнение 4,7*(-4y-3)-3,5(6-2y)=0,3

Answer 1

$4.7*(-4y-3)-3.5*(6-2y)=0.3 \ -18.8y-14.1-21+7y=0.3 \ -35.1-11.8y=0.3 \ -11.8y=0.3+35.1 \ -11.8y=35.4 \ 11.8y=-35.4 \ y=(-35.4):11.8 \ y=-3$