Question

Помогите систему решить :
1 /х + 1/у=1/3

ху= -18

Answer 1

1/x+1/y=1/3
xy=-18⇒x=-18/y
-y/18+1/y=1/3
-y²+18=6y
y²+6y-18=0
D=36*72=108    √D=6√3
y1=(-6-6√3)/2=-3-3√3⇒x1=-18/(-3-3√3)=6/(1+√3)=6(-1+√3)/(1-3)=3(1-√3)
y2=(-6+6√3)/2=-3+3√3⇒x2=-18/(-3+3√3)=6/(1-√3)=6(1+√3)/(1-3)=-3(√3+1)

Answer 2

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