Question

Lim SinX Sin2X Помогите пожалуйста
        5X²

Answer 1

$lim_{x to 0} frac{sinxsin2x}{5 x^{2} }= lim_{x to 0} frac{sinx2sinxcosx}{5 x^{2} }= ( lim_{x to 0} frac{sinx}{x} )^{2}*$$lim_{x to 0} frac{2cosx}{5}=1* frac{2cos0}{5}= frac{2}{5}$