Question

Помогите решить 19 задание 

Answer 1

1)3cosπ-1/2sinπ/2+ctg3π/2=3*(-1)-1/2*1+0=-3,5
2)2sinπ/3-√2tgπ/4+1/2cosπ/4=2*√3/2-√2*1+1/2*√2/2=√3-3√2/4=(4√3-3√2)/4
3)2sinπ/6-cosπ/4+tgπ/6=2*1/2-√2/2+√3/3=(3-3√2+2√3)/6
4)tgπ/3-sinπ/4+cosπ/6=√3-√2/2+√3/2=(3√3-√2)/2