Question

2arcsin(-1)-3arcctg3+arccos(-2/2)

Answer 1

2arcsin(-1)-3arcctg√3+arccos(-√2/2)=
= 2(-π/2)-3·(π/6)+(π-π/4)=
= -π-(π/2)+3π/4=
= -3π/2+3π/4=-3π/4