Question

pomogite reshitj primer a

Answer 1

а) 4/(Х²-4) = 5/(Х-2) - 3/(Х+2) или 4/[(Х+2)*(Х-2)] =5/(Х-2) - 3/(Х+2). Отсюда
4 = 5*(Х+2) - 3*(Х-2). 2Х=-12  Х= -6.
b) Х/(Х+3) - 1/(Х-3) = 16/(Х²-9) или Х/(Х+3) - 1/(Х-3) = 16/[(Х+3(X-3)] Отсюда
Х(Х-3) - (Х+3) = 18. Х² - 4Х -21 =0.
Х1=2+ √(4+21) = 2+5 = 7.
Х2=2-5= -3.