Question

Решите номер 32.Есть вложение.

Answer 1

$frac{3x^2-2x}{6-7x-3x^2} = frac{x(3x-2)}{-3(x- frac{2}{3})(x+3)} } =frac{x(3x-2)}{-(3x-2)(x+3)} } = -frac{x}{x+3 } \ 6-7x-3x^2=0 \ 3x^2+7x-6=0 \ D=49+4cdot3cdot6=121 \ x_1= frac{-7-11}{6} =-3 \ x_2= frac{-7+11}{6} = frac{2}{3}$

$frac{7x^2-x}{2-13x-7x^2} = frac{7x^2-x}{-7(x- frac{1}{7})(x+2)} =frac{x(7x-1)}{-(7x- 1)(x+2)} = -frac{x}{x+2} \ 2-13x-7x^2=0 \ 7x^2+13x-2=0 \ D=169+2cdot7cdot4=225 \ x_1= frac{-13-15}{14} =-2 \ x_2= frac{-13+15}{14} = frac{1}{7}$