Question

Решите номер 39.Есть вложение.

Answer 1

$1- cfrac{1}{1- cfrac{a}{1- frac{1}{a+1} } } =1- cfrac{1}{1- cfrac{a}{ frac{a+1-1}{a+1} } } = 1- cfrac{1}{1- cfrac{a}{ frac{a}{a+1} } } =1- frac{1}{1- a-1} } } = \ =1- frac{1}{- a} } } = frac{a+1}{ a} } }$

$1+ cfrac{x}{1- cfrac{x}{x+ frac{x}{x-1} } } =1+cfrac{x}{1- cfrac{x}{ frac{x^2-x+x}{x-1} } } = 1+ cfrac{x}{1- cfrac{x}{ frac{x^2}{x-1} } } =1+ cfrac{x}{1- frac{x-1}{x } } = \ =1+ cfrac{x}{ frac{x-x+1}{x } } =1+ cfrac{x}{ frac{1}{x } } =1+x^2$