Question

cos(альфа+125гр)/sin(альфа+35гр)

Answer 1

$frac{cos( alpha +125^0)}{sin( alpha +35^0)}= frac{cos alpha *cos125^0-sin alpha sin125^0}{sin alpha cos35^0+cos alpha *sin35^0}=frac{cos alpha cos(90^0+35^0)-sin alpha *sin(90^0+35^0)}{sin alpha cos35^0+cos alpha sin35^0}$ = $frac{cos alpha*(-sin35^0)-sin alpha *cos35^0}{sin alpha cos35^0+cos alpha sin35^0} =frac{-(cos alpha*sin35^0+sin alpha *cos35^0)}{sin alpha cos35^0+cos alpha sin35^0} =-1$