Question

помогите, пожалуйста, решить

Answer 1

$(sqrt{3 frac{6}{7}} - sqrt{1 frac{5}{7}}): sqrt{frac{3}{28}} = (sqrt{frac{27}{7}} - sqrt{frac{12}{7}})cdotsqrt{frac{28}{3}} = sqrt{frac{27}{7}}cdotsqrt{frac{28}{3}} - \ -sqrt{frac{12}{7}}cdotsqrt{frac{28}{3}} = sqrt{frac{27cdot28}{7cdot3}} - sqrt{frac{12cdot28}{7cdot3}} = sqrt{9cdot4} - sqrt{4cdot4} = 6-4 = 2$

$frac{sqrt[9]{7}cdotsqrt[18]{7}}{sqrt[13]{7}} = frac{7^{frac{1}{9}}cdot7^{frac{1}{18}}}{7^{frac{1}{13}}}=7^{frac{1}{9}+frac{1}{18}-frac{1}{13}}=7^{frac{26+13-18}{234}}=7^{frac{21}{234}}=7^{frac{7}{78}}= sqrt[78]{7^7}$