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решение на фотографии
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СПАСИБО!!!
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2) ![intlimits {( frac{4x^{3}}{3}- frac{3x^{2}}{2}+8)} , dx=frac{4x^{4}}{4*3}-frac{3x^{3}}{3*2}+8x+C=frac{x^{4}}{3}-frac{x^{3}}{2}+8x+C intlimits {( frac{4x^{3}}{3}- frac{3x^{2}}{2}+8)} , dx=frac{4x^{4}}{4*3}-frac{3x^{3}}{3*2}+8x+C=frac{x^{4}}{3}-frac{x^{3}}{2}+8x+C](https://tex.z-dn.net/?f=+intlimits+%7B%28+frac%7B4x%5E%7B3%7D%7D%7B3%7D-+frac%7B3x%5E%7B2%7D%7D%7B2%7D%2B8%29%7D+%2C+dx%3Dfrac%7B4x%5E%7B4%7D%7D%7B4%2A3%7D-frac%7B3x%5E%7B3%7D%7D%7B3%2A2%7D%2B8x%2BC%3Dfrac%7Bx%5E%7B4%7D%7D%7B3%7D-frac%7Bx%5E%7B3%7D%7D%7B2%7D%2B8x%2BC)
4)![intlimits^4_0 {(1+e^{x})} , dx=x+e^{x}|^{4}_{0}=4+e^{4}-0-e^{0}=4+e^{4}-1=3+e^{4} intlimits^4_0 {(1+e^{x})} , dx=x+e^{x}|^{4}_{0}=4+e^{4}-0-e^{0}=4+e^{4}-1=3+e^{4}](https://tex.z-dn.net/?f=+intlimits%5E4_0+%7B%281%2Be%5E%7Bx%7D%29%7D+%2C+dx%3Dx%2Be%5E%7Bx%7D%7C%5E%7B4%7D_%7B0%7D%3D4%2Be%5E%7B4%7D-0-e%5E%7B0%7D%3D4%2Be%5E%7B4%7D-1%3D3%2Be%5E%7B4%7D)
5)![frac{3-2i}{1+3i}= frac{(3-2i)*(1-3i)}{(1+3i)(1-3i)}=frac{3-9i-2i+6i^{2}}{1-9i^{2}}= frac{3-2i}{1+3i}= frac{(3-2i)*(1-3i)}{(1+3i)(1-3i)}=frac{3-9i-2i+6i^{2}}{1-9i^{2}}=](https://tex.z-dn.net/?f=+frac%7B3-2i%7D%7B1%2B3i%7D%3D+frac%7B%283-2i%29%2A%281-3i%29%7D%7B%281%2B3i%29%281-3i%29%7D%3Dfrac%7B3-9i-2i%2B6i%5E%7B2%7D%7D%7B1-9i%5E%7B2%7D%7D%3D)
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