Question

а+1 / 2а(а-1) - а-1/ 2а(а+1)

Answer 1

$frac{a+1}{2a(a-1)}-frac{a-1}{2a(a+1)}=frac{(a+1)^2-(a-1)^2}{2a(a-1)(a+1)}=frac{4a}{2a(a^2-1)}=frac{2}{a^2-1}$