1)0.8/(1-1/9)= найдите значение выражения
2)5-2x=11-7(x-2) решите уравнение
3)(a+x)/a:(ax+x^2)/a^2 при а=67 ,х=-25
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![frac{0.8}{1- frac{1}{9} } =frac{0.8}{ frac{9}{9} - frac{1}{9} } =frac{ frac{8}{10} }{ frac{8}{9} } = frac{4}{5} cdot frac{9}{8}= frac{9}{10} =0.9 frac{0.8}{1- frac{1}{9} } =frac{0.8}{ frac{9}{9} - frac{1}{9} } =frac{ frac{8}{10} }{ frac{8}{9} } = frac{4}{5} cdot frac{9}{8}= frac{9}{10} =0.9](https://tex.z-dn.net/?f=frac%7B0.8%7D%7B1-+frac%7B1%7D%7B9%7D+%7D+%3Dfrac%7B0.8%7D%7B+frac%7B9%7D%7B9%7D+-+frac%7B1%7D%7B9%7D+%7D+%3Dfrac%7B+frac%7B8%7D%7B10%7D+%7D%7B++frac%7B8%7D%7B9%7D+%7D+%3D+frac%7B4%7D%7B5%7D+cdot+frac%7B9%7D%7B8%7D%3D+frac%7B9%7D%7B10%7D+%3D0.9+)
============ 2 ============
![5-2x=11-7(x-2)\
5-2x=11-7x+14\
-2x+7x=25-5\
5x=20\
x=4 5-2x=11-7(x-2)\
5-2x=11-7x+14\
-2x+7x=25-5\
5x=20\
x=4](https://tex.z-dn.net/?f=5-2x%3D11-7%28x-2%29%5C%0A5-2x%3D11-7x%2B14%5C%0A-2x%2B7x%3D25-5%5C%0A5x%3D20%5C%0Ax%3D4)
============ 3 ============
![frac{a+x}{a} : frac{ax+x^2}{a^2} =frac{a+x}{a} cdot frac{a^2}{x(a+x)} = frac{a}{x} \\
a=67, x=-25 Rightarrow frac{67}{-25}=-2.68 frac{a+x}{a} : frac{ax+x^2}{a^2} =frac{a+x}{a} cdot frac{a^2}{x(a+x)} = frac{a}{x} \\
a=67, x=-25 Rightarrow frac{67}{-25}=-2.68](https://tex.z-dn.net/?f=frac%7Ba%2Bx%7D%7Ba%7D+%3A++frac%7Bax%2Bx%5E2%7D%7Ba%5E2%7D+%3Dfrac%7Ba%2Bx%7D%7Ba%7D+cdot++frac%7Ba%5E2%7D%7Bx%28a%2Bx%29%7D+%3D+frac%7Ba%7D%7Bx%7D+%5C%5C%0Aa%3D67%2C+x%3D-25+Rightarrow+frac%7B67%7D%7B-25%7D%3D-2.68)
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