Question

Решите пожалуйста........

Answer 1

00000000000000000000000000000000

Answer 2

1) $( frac{x}{x+1} + frac{1}{1} )* frac{1+x}{2x-1} =( frac{x}{x+1} + frac{x+1}{x+1} )*frac{1+x}{2x-1}= frac{x+x+1}{x+1} *frac{1+x}{2x-1}=$
$= frac{2x+1}{x+1} *frac{x+1}{2x-1}= frac{2x+1}{2x-1}$

2) $( frac{2m+1}{2m-1} - frac{2m-1}{2m+1} ): frac{4m}{10m-5} =( frac{(2m+1)^{2} }{(2m-1)(2m+1)} - frac{(2m-1)^{2} }{(2m-1)(2m+1)} )* frac{5(2m-1)}{4m} =$
$= frac{(2m+1)^{2}-(2m-1)^{2} }{(2m-1)(2m+1)} * frac{5(2m-1)}{4m} = frac{5(2m+1+2m-1)(2m+1-2m+1)}{4m(2m+1)} =$
$= frac{5*4m*2}{4m(2m+1)} = frac{10}{2m+1}$

3) $frac{ a^{2}-25 }{a+3} * frac{1}{ a^{2}+5a } - frac{a+5}{a^{2}-3a } = frac{(a-5)(a+5)}{a+3} * frac{1}{a(a+5)} - frac{a+5}{a(a-3)} =$
$= frac{a-5}{a(a+3)} - frac{a+5}{a(a-3)} = frac{(a-5)(a-3)}{a(a+3)(a-3)} - frac{(a+5)(a+3)}{a(a+3)(a-3)} =$
$=frac{(a-5)(a-3)-(a+5)(a+3)}{a(a-3)(a+3)} = frac{ a^{2}-5a-3a+15- a^{2}-5a-3a-15 }{a(a-3)(a+3)} = frac{-16a}{a( a^{2}-9) } =- frac{16}{ a^{2}-9 }$