Question

Lim (x->4) (x^2-16 / x^2 - 4x ) =

Answer 1

$lim_{x to 4} frac{x^2-16}{x^2-4x}= lim_{x to 4} frac{(x-4)(x+4)}{x(x-4)}= lim_{x to 4} frac{x+4}{x}=2$