Question

РЕШИТЬ СИСТЕМУ УРАВНЕНИЯ! Срочнооо ; X в квадрате -5xy=10
X-5y=1

Answer 1

$left { {{x^2-5xy=10} atop {x-5y=1}} right. => left { {{x=1-5y} atop {(1-5y)^2-5y(1-5y)=10}} right.=> left { {{x=1-5y} atop {(1-5y)(1-5y-5y)=10}} right. =>\ => left { {{x=1-5y} atop {-10y-5y+1-50y^2=0}} right. => left { {{x=1-5y} atop {50y^2+15y-1=0}} right.$
50y^2+15y-1=0
D=225+200=425
x1 = (245-15)/100=2.3
x2 = -260/100=-2.6
y1 = 1- 2.3 * 5= -10.5
y2= 1+2.6*5=14
S={(2.3;  -10.5);  (-2.6; 14 )}