Question

Решить уравнение.
а)ײ-5√2×+12=0
б)ײ+2√3-72=0
в)у²-6у+7=0
г)р²-10р+7=0

Answer 1

а)ײ-5√2×+12=0
D=50-4*12=2
x1=(5√2-√2)/2
x2=(5√2+√2)/2

б)ײ+2√3-72=0
D=12+4*72=300
x12=(-2√3+-√300)/2

в)у²-6у+7=0
D=36-4*7=4
y1=(6-2)/2=2
y2=(6+2)/2=4

г)р²-10р+7=0
D=100-4*7=68
x12=(10+-√68)/2