Question

сократите дробь -0,4x^2-0.3x+0,7/x^2-2x+1

Answer 1

-0.4x²-0,3x+0,7=-0,1(4x²+3x-7)=-0,1·4(x-1)(x-(-7/4))
D=3²-4·4·(-7)=9+112=121
x=(-3-11)/8=-7/4       или      х=(-3+11)/8=1

$frac{-0,4(x-1)(x-(- frac{7}{4})) }{(x-1) ^{2} }= frac{-4x-7}{10(x-1)}$