Question

ПРОШУ ОЧЕНЬ НАДО ПОМОГИТЕ РЕШИТЬ!!!!:%(((((((((((((((((((((((((((

Answer 1

(1/((b-y)(y-5))-1/((b-y)(b-5))-1/((b-5)(y-5))·(b²-9y²)/(b⁴+y⁴)=
=((b-5)-(y-5)-(b-y)/(b-y)(y-5)(b-5)·(b²-9y²)/(b⁴+y⁴)=
=(b-5-y+5-b+y)·(b²-9y²)/(b-y)(y-5)(b-5)(b⁴+y⁴)=0·(b²-9y²)/(b-y)(y-5)(b-5)(b⁴+y⁴)=0