Question

Решите Уравнения: (8Класс)
1)2x^2-14=0
2)x(x-5)=-4

Answer 1

1) 2*х²-14=0
2*х²=14
х²=7
х₁=√7
х₂=-√7
2)х*(х-5)=-4
х²-5х+4=0
Д=(-5)²-4*4=25-16=9
х₁=5+3/2=4
х₂=5-3/2=1

Answer 2

$1)2 x^{2} -14=0 \ 2 x^{2} =14 \ x^{2} =7 \ x=+- sqrt{7} \ \ 2)x(x-5)=-4 \ x^{2} -5x+4=0 \ D=25-16=9 \ sqrt{D} =3 \ x_{1} = frac{5+3}{2} = frac{8}{2} =4 \ x_{2} = frac{5-3}{2} = frac{2}{2} =1$