Question

$3^{28} :27^9$ - расписать, спасибо.

Answer 1

$alpha ^ beta : alpha ^gamma= alpha ^{ beta -gamma} \ ( alpha ^ beta )^gamma= alpha ^{ beta gamma}$

$3^{28}:27^9= cfrac{3^{28}}{27^9} =cfrac{3^{28}}{(3^3)^9} =cfrac{3^{28}}{3^{3cdot9}} =cfrac{3^{28}}{3^{27}} =3^{28-27}=3^1=3$