Question

Помогите пожалуйстаааа

Answer 1

$y`=((2x^{3}+3x^{ frac{4}{5} })(3x- x^{3}))`=[(uv)`=u`v+uv`]= \ =(2x^{3}+3x^{ frac{4}{5} })`(3x- x^{3})+ (2x^{3}+3x^{ frac{4}{5} })(3x- x^{3})`= \ =(6 x^{2} + 3cdot frac{4}{5}x^{ frac{4}{5}-1 })(3x- x^{3})+(2x^{3}+3x^{ frac{4}{5} })(3- 3x^{2})= \ =18 x^{3} + frac{36}{5}x^{ frac{4}{5}-1+1 } -6 x^{5} - frac{12}{5} x^{frac{4}{5}-1+3} +6 x^{3}+9x^{ frac{4}{5} }-6 x^{5}-9 x^{ frac{4}{5}+2 }= \=-12 x^{5}+24x^{3}+( frac{36}{5}+9)x^{ frac{4}{5} }-( frac{12}{5}+9)x^{ frac{4}{5}+2 } =$
$=-12 x^{5}+24x ^{3}+( frac{81}{5})x^{ frac{4}{5} }-( frac{57}{5})x^{ frac{14}{5}}$