Question

решите неравенство: $log_{0.5}log_2(x^2-2x-1)leq0$

help plzzz!

Answer 1

$log_{0,5}log_{2}(x^{2}-2x-1)leq0$

$log_{2}(x^{2}-2x-1)geq0$

$log_{2}(x^{2}-2x-1)geq log_{2}1$

$x^{2}-x-1geq 1$$x^{2}-x-2geq 0$

$(x-2)(x+1)geq 0$

 

+                   -                   +

_______(-1)______(2)______

 

$(-infty;-1]cup[2;+infty)$