Question

Найти нули функции
1) y=x+7x+12
2)y=[x]-3

Answer 1

1) y=x+7x+12
x+7x+12=0
D=49-48=1
x₁=(-7-1)/2=-4
x₂=(-7+1)/2=-3

2) y=|x|-3
|x|-3=0
x-3=0
x=3