Question

номер 6)))))))))))))))

Answer 1

$sqrt{2x+48} =-x \ left { {{( sqrt{2x+48})^2 =(-x)^2} atop {-x geq 0}} right. \ left { {{{2x+48 =x^2} atop {x leq 0}} right. \ left { {{{x^2-2x-48=0} atop {x leq 0}} right. \ left { {{{(x-8)(x+6)=0} atop {x leq 0}} right. \ left { {{{x_1=8; x_2=-6} atop {x leq 0}} right. \ x=-6$
Ответ: -6