Question

решите уравнение:1)7целых 3/10+25/28×=8целых13/35;
2)3целых1/3-1целая1/20×=1целая14/15;
3)3/8×+7/12×-5/6×=9/32;

Answer 1

$7 frac{3}{10}+ frac{25}{28}x=8 frac{13}{35} \ \ frac{25}{28}x= frac{293}{35}- frac{73}{10} \ \ frac{25}{28}x= frac{586-511}{70} \ \ x= frac{15}{14}* frac{28}{25} \ \ x=1 frac{1}{5}$

$3 frac{1}{3}-1 frac{1}{20}x=1 frac{14}{15} \ \ - frac{21}{20}x= frac{29}{15}- frac{10}{3} \ \ - frac{21}{20}x= frac{29-50}{15} \ \ x=- frac{21}{15}*(- frac{20}{21}) \ \ x=1 frac{1}{3}$

$frac{3}{8}x+ frac{7}{12}x- frac{5}{6}x= frac{9}{32} \ \ (frac{9+14-20}{24})x= frac{9}{32} \ \ frac{1}{8}x= frac{9}{32} \ \ x= frac{9}{32}* frac{8}{1} \ \ x=2 frac{1}{4}$